Method #2

The general solution in finding the number of zeros in 100!, 1000!, 10 000!, 100 000!, 1 000 000! …

Where,                 N is one of the following: 100, 1 000, 10 000, …

                Condition: Only accept the term that is when the numerator is greater than the denominator.

Example:                          where N = 100

                =  (Numerator is greater than the denominator.)

                 =  (Do not accept this, because the numerator is less than the denominator.)

Going back to the equation:

Note: Do not include the term and the terms after that since the denominator is greater than the numerator.

Therefore, there are 24 consecutive zeroes are there at the end of 100!